Base | Representation |
---|---|
bin | 11100110101100110010010… |
… | …01100000111011011011101 |
3 | 22022112100022200120001202211 |
4 | 32122303021030013123131 |
5 | 31302434412233222332 |
6 | 342512040432320421 |
7 | 16233346535003320 |
oct | 1632631114073335 |
9 | 268470280501684 |
10 | 63414272554717 |
11 | 19229929717847 |
12 | 714213b6a3111 |
13 | 294cc2b937176 |
14 | 11933a51767b7 |
15 | 74e83dc10447 |
hex | 39acc93076dd |
63414272554717 has 4 divisors (see below), whose sum is σ = 72473454348256. Its totient is φ = 54355090761180.
The previous prime is 63414272554697. The next prime is 63414272554723. The reversal of 63414272554717 is 71745527241436.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-63414272554717 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (63414272554757) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4529590896759 + ... + 4529590896772.
It is an arithmetic number, because the mean of its divisors is an integer number (18118363587064).
Almost surely, 263414272554717 is an apocalyptic number.
It is an amenable number.
63414272554717 is a deficient number, since it is larger than the sum of its proper divisors (9059181793539).
63414272554717 is an equidigital number, since it uses as much as digits as its factorization.
63414272554717 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9059181793538.
The product of its digits is 39513600, while the sum is 58.
The spelling of 63414272554717 in words is "sixty-three trillion, four hundred fourteen billion, two hundred seventy-two million, five hundred fifty-four thousand, seven hundred seventeen".
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