Base | Representation |
---|---|
bin | 111011000100011011… |
… | …000100111011000101 |
3 | 20001201012021112112212 |
4 | 323010123010323011 |
5 | 2014343243141113 |
6 | 45045333153205 |
7 | 4403505250124 |
oct | 730433047305 |
9 | 201635245485 |
10 | 63424974533 |
11 | 24997821128 |
12 | 10360a8b805 |
13 | 5c9a1b873b |
14 | 30d96c1abb |
15 | 19b32900a8 |
hex | ec46c4ec5 |
63424974533 has 2 divisors, whose sum is σ = 63424974534. Its totient is φ = 63424974532.
The previous prime is 63424974421. The next prime is 63424974563. The reversal of 63424974533 is 33547942436.
63424974533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 62803868449 + 621106084 = 250607^2 + 24922^2 .
It is a cyclic number.
It is not a de Polignac number, because 63424974533 - 218 = 63424712389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (63424974563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31712487266 + 31712487267.
It is an arithmetic number, because the mean of its divisors is an integer number (31712487267).
Almost surely, 263424974533 is an apocalyptic number.
It is an amenable number.
63424974533 is a deficient number, since it is larger than the sum of its proper divisors (1).
63424974533 is an equidigital number, since it uses as much as digits as its factorization.
63424974533 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6531840, while the sum is 50.
The spelling of 63424974533 in words is "sixty-three billion, four hundred twenty-four million, nine hundred seventy-four thousand, five hundred thirty-three".
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