Base | Representation |
---|---|
bin | 11100110110011001000110… |
… | …11000010110010000110001 |
3 | 22022121221202002021000112201 |
4 | 32123030203120112100301 |
5 | 31303411301202430132 |
6 | 342532352005023201 |
7 | 16235333613225013 |
oct | 1633144330262061 |
9 | 268557662230481 |
10 | 63441555514417 |
11 | 1923a45a196223 |
12 | 71474946b4b01 |
13 | 295268912a5c2 |
14 | 11948327d41b3 |
15 | 7503d903a2e7 |
hex | 39b323616431 |
63441555514417 has 2 divisors, whose sum is σ = 63441555514418. Its totient is φ = 63441555514416.
The previous prime is 63441555514369. The next prime is 63441555514453. The reversal of 63441555514417 is 71441555514436.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47665160768016 + 15776394746401 = 6903996^2 + 3971951^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-63441555514417 is a prime.
It is a super-2 number, since 2×634415555144172 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (63441555514217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31720777757208 + 31720777757209.
It is an arithmetic number, because the mean of its divisors is an integer number (31720777757209).
Almost surely, 263441555514417 is an apocalyptic number.
It is an amenable number.
63441555514417 is a deficient number, since it is larger than the sum of its proper divisors (1).
63441555514417 is an equidigital number, since it uses as much as digits as its factorization.
63441555514417 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20160000, while the sum is 55.
The spelling of 63441555514417 in words is "sixty-three trillion, four hundred forty-one billion, five hundred fifty-five million, five hundred fourteen thousand, four hundred seventeen".
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