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63441555514453 is a prime number
BaseRepresentation
bin11100110110011001000110…
…11000010110010001010101
322022121221202002021000121001
432123030203120112101111
531303411301202430303
6342532352005023301
716235333613225064
oct1633144330262125
9268557662230531
1063441555514453
111923a45a196256
1271474946b4b31
13295268912a61c
1411948327d41db
157503d903a31d
hex39b323616455

63441555514453 has 2 divisors, whose sum is σ = 63441555514454. Its totient is φ = 63441555514452.

The previous prime is 63441555514417. The next prime is 63441555514481. The reversal of 63441555514453 is 35441555514436.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62148279362724 + 1293276151729 = 7883418^2 + 1137223^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-63441555514453 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 63441555514394 and 63441555514403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (63441555515453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31720777757226 + 31720777757227.

It is an arithmetic number, because the mean of its divisors is an integer number (31720777757227).

Almost surely, 263441555514453 is an apocalyptic number.

It is an amenable number.

63441555514453 is a deficient number, since it is larger than the sum of its proper divisors (1).

63441555514453 is an equidigital number, since it uses as much as digits as its factorization.

63441555514453 is an evil number, because the sum of its binary digits is even.

The product of its digits is 43200000, while the sum is 55.

The spelling of 63441555514453 in words is "sixty-three trillion, four hundred forty-one billion, five hundred fifty-five million, five hundred fourteen thousand, four hundred fifty-three".