Base | Representation |
---|---|
bin | 111011001010011010… |
… | …001111000000110101 |
3 | 20001222012021112201201 |
4 | 323022122033000311 |
5 | 2020100001321023 |
6 | 45103322052501 |
7 | 4406135064262 |
oct | 731232170065 |
9 | 201865245651 |
10 | 63525417013 |
11 | 24a39495043 |
12 | 1038a64a131 |
13 | 5cb4c55766 |
14 | 3108b8a269 |
15 | 19bbed0bad |
hex | eca68f035 |
63525417013 has 2 divisors, whose sum is σ = 63525417014. Its totient is φ = 63525417012.
The previous prime is 63525416987. The next prime is 63525417023. The reversal of 63525417013 is 31071452536.
63525417013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50273263089 + 13252153924 = 224217^2 + 115118^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-63525417013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (63525417023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31762708506 + 31762708507.
It is an arithmetic number, because the mean of its divisors is an integer number (31762708507).
Almost surely, 263525417013 is an apocalyptic number.
It is an amenable number.
63525417013 is a deficient number, since it is larger than the sum of its proper divisors (1).
63525417013 is an equidigital number, since it uses as much as digits as its factorization.
63525417013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75600, while the sum is 37.
Adding to 63525417013 its reverse (31071452536), we get a palindrome (94596869549).
The spelling of 63525417013 in words is "sixty-three billion, five hundred twenty-five million, four hundred seventeen thousand, thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •