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63540145501041 = 3111925458954577
BaseRepresentation
bin11100111001010000101111…
…10011010011001101110001
322022222101012222201021001210
432130220113303103031301
531312020204222013131
6343045535002350333
716245424016254236
oct1634502763231561
9268871188637053
1063540145501041
1119278251713410
12716260a1bb3a9
13295ba6b7938b1
14119950649778d
15752c595a3146
hex39ca17cd3371

63540145501041 has 8 divisors (see below), whose sum is σ = 92422029819744. Its totient is φ = 38509179091520.

The previous prime is 63540145501033. The next prime is 63540145501127. The reversal of 63540145501041 is 14010554104536.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 63540145501041 - 23 = 63540145501033 is a prime.

It is not an unprimeable number, because it can be changed into a prime (63540145501841) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 962729477256 + ... + 962729477321.

It is an arithmetic number, because the mean of its divisors is an integer number (11552753727468).

Almost surely, 263540145501041 is an apocalyptic number.

It is an amenable number.

63540145501041 is a deficient number, since it is larger than the sum of its proper divisors (28881884318703).

63540145501041 is a wasteful number, since it uses less digits than its factorization.

63540145501041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1925458954591.

The product of its (nonzero) digits is 144000, while the sum is 39.

Adding to 63540145501041 its reverse (14010554104536), we get a palindrome (77550699605577).

The spelling of 63540145501041 in words is "sixty-three trillion, five hundred forty billion, one hundred forty-five million, five hundred one thousand, forty-one".

Divisors: 1 3 11 33 1925458954577 5776376863731 21180048500347 63540145501041