Base | Representation |
---|---|
bin | 101110011011011011000… |
… | …0100111110101110110001 |
3 | 211121000200112000222011001 |
4 | 1130312312010332232301 |
5 | 1314021423241142033 |
6 | 21323232255322001 |
7 | 1226006066132464 |
oct | 134666604765661 |
9 | 24530615028131 |
10 | 6381081193393 |
11 | 2040223a85395 |
12 | 870843220301 |
13 | 37396c2bacca |
14 | 180bbb5112db |
15 | b0ebe9d3e7d |
hex | 5cdb613ebb1 |
6381081193393 has 2 divisors, whose sum is σ = 6381081193394. Its totient is φ = 6381081193392.
The previous prime is 6381081193379. The next prime is 6381081193397. The reversal of 6381081193393 is 3933911801836.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5892134826384 + 488946367009 = 2427372^2 + 699247^2 .
It is a cyclic number.
It is not a de Polignac number, because 6381081193393 - 225 = 6381047638961 is a prime.
It is not a weakly prime, because it can be changed into another prime (6381081193397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3190540596696 + 3190540596697.
It is an arithmetic number, because the mean of its divisors is an integer number (3190540596697).
Almost surely, 26381081193393 is an apocalyptic number.
It is an amenable number.
6381081193393 is a deficient number, since it is larger than the sum of its proper divisors (1).
6381081193393 is an equidigital number, since it uses as much as digits as its factorization.
6381081193393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2519424, while the sum is 55.
The spelling of 6381081193393 in words is "six trillion, three hundred eighty-one billion, eighty-one million, one hundred ninety-three thousand, three hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •