Base | Representation |
---|---|
bin | 111011100011001101… |
… | …001001000000100011 |
3 | 20010001012001102121121 |
4 | 323203031021000203 |
5 | 2021423000234242 |
6 | 45212502233111 |
7 | 4422346026244 |
oct | 734315110043 |
9 | 203035042547 |
10 | 63941414947 |
11 | 25132297493 |
12 | 10485a25797 |
13 | 60501a8997 |
14 | 3148116ccb |
15 | 19e37a4667 |
hex | ee3349023 |
63941414947 has 2 divisors, whose sum is σ = 63941414948. Its totient is φ = 63941414946.
The previous prime is 63941414903. The next prime is 63941414981. The reversal of 63941414947 is 74941414936.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 63941414947 - 227 = 63807197219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 63941414894 and 63941414903.
It is not a weakly prime, because it can be changed into another prime (63941514947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31970707473 + 31970707474.
It is an arithmetic number, because the mean of its divisors is an integer number (31970707474).
Almost surely, 263941414947 is an apocalyptic number.
63941414947 is a deficient number, since it is larger than the sum of its proper divisors (1).
63941414947 is an equidigital number, since it uses as much as digits as its factorization.
63941414947 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2612736, while the sum is 52.
The spelling of 63941414947 in words is "sixty-three billion, nine hundred forty-one million, four hundred fourteen thousand, nine hundred forty-seven".
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