Search a number
-
+
63941414903 is a prime number
BaseRepresentation
bin111011100011001101…
…001000111111110111
320010001012001102112222
4323203031020333313
52021423000234103
645212502232555
74422346026152
oct734315107767
9203035042488
1063941414903
1125132297453
1210485a2575b
1360501a8962
143148116c99
1519e37a4638
hexee3348ff7

63941414903 has 2 divisors, whose sum is σ = 63941414904. Its totient is φ = 63941414902.

The previous prime is 63941414869. The next prime is 63941414947. The reversal of 63941414903 is 30941414936.

It is an a-pointer prime, because the next prime (63941414947) can be obtained adding 63941414903 to its sum of digits (44).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 63941414903 - 212 = 63941410807 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (63941414503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31970707451 + 31970707452.

It is an arithmetic number, because the mean of its divisors is an integer number (31970707452).

Almost surely, 263941414903 is an apocalyptic number.

63941414903 is a deficient number, since it is larger than the sum of its proper divisors (1).

63941414903 is an equidigital number, since it uses as much as digits as its factorization.

63941414903 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 279936, while the sum is 44.

The spelling of 63941414903 in words is "sixty-three billion, nine hundred forty-one million, four hundred fourteen thousand, nine hundred three".