Base | Representation |
---|---|
bin | 101110100111100011001… |
… | …1011101111111001101111 |
3 | 211200111220120210210210011 |
4 | 1131033012123233321233 |
5 | 1314433243100314244 |
6 | 21343220501154051 |
7 | 1230620353216465 |
oct | 135170633577157 |
9 | 24614816723704 |
10 | 6407125401199 |
11 | 205027928a176 |
12 | 8758b13bb927 |
13 | 37625cc6c563 |
14 | 18216c432835 |
15 | b19e61bb434 |
hex | 5d3c66efe6f |
6407125401199 has 2 divisors, whose sum is σ = 6407125401200. Its totient is φ = 6407125401198.
The previous prime is 6407125401151. The next prime is 6407125401217. The reversal of 6407125401199 is 9911045217046.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6407125401199 - 217 = 6407125270127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6407125401499) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3203562700599 + 3203562700600.
It is an arithmetic number, because the mean of its divisors is an integer number (3203562700600).
Almost surely, 26407125401199 is an apocalyptic number.
6407125401199 is a deficient number, since it is larger than the sum of its proper divisors (1).
6407125401199 is an equidigital number, since it uses as much as digits as its factorization.
6407125401199 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 49.
The spelling of 6407125401199 in words is "six trillion, four hundred seven billion, one hundred twenty-five million, four hundred one thousand, one hundred ninety-nine".
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