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64113381108 = 223273753137947
BaseRepresentation
bin111011101101011101…
…001000111011110100
320010111011122012211200
4323231131020323310
52022301011143413
645241524132500
74426534514310
oct735535107364
9203434565750
1064113381108
1125210372187
1210513537130
1360799c8bca
143162cbcb40
151a03922573
hexeed748ef4

64113381108 has 288 divisors, whose sum is σ = 195432217344. Its totient is φ = 17340770304.

The previous prime is 64113381083. The next prime is 64113381119. The reversal of 64113381108 is 80118331146.

64113381108 is a `hidden beast` number, since 64 + 113 + 381 + 108 = 666.

It is a super-2 number, since 2×641133811082 (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 67701091 + ... + 67702037.

It is an arithmetic number, because the mean of its divisors is an integer number (678584088).

Almost surely, 264113381108 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 64113381108, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (97716108672).

64113381108 is an abundant number, since it is smaller than the sum of its proper divisors (131318836236).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

64113381108 is a wasteful number, since it uses less digits than its factorization.

64113381108 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1191 (or 1186 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 36.

The spelling of 64113381108 in words is "sixty-four billion, one hundred thirteen million, three hundred eighty-one thousand, one hundred eight".