Base | Representation |
---|---|
bin | 11101001001111100101000… |
… | …11001000101011011101011 |
3 | 22102000012001201012010221121 |
4 | 32210332110121011123223 |
5 | 31400413334401244321 |
6 | 344205153031520111 |
7 | 16335021315620461 |
oct | 1644762431053353 |
9 | 272005051163847 |
10 | 64113466431211 |
11 | 1947940640296a |
12 | 7235752229037 |
13 | 29a0b49088c42 |
14 | 11b917339a831 |
15 | 762b12131441 |
hex | 3a4f946456eb |
64113466431211 has 2 divisors, whose sum is σ = 64113466431212. Its totient is φ = 64113466431210.
The previous prime is 64113466431139. The next prime is 64113466431251. The reversal of 64113466431211 is 11213466431146.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-64113466431211 is a prime.
It is a super-2 number, since 2×641134664312112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (64113466431251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32056733215605 + 32056733215606.
It is an arithmetic number, because the mean of its divisors is an integer number (32056733215606).
Almost surely, 264113466431211 is an apocalyptic number.
64113466431211 is a deficient number, since it is larger than the sum of its proper divisors (1).
64113466431211 is an equidigital number, since it uses as much as digits as its factorization.
64113466431211 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 248832, while the sum is 43.
The spelling of 64113466431211 in words is "sixty-four trillion, one hundred thirteen billion, four hundred sixty-six million, four hundred thirty-one thousand, two hundred eleven".
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