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64113466431139 is a prime number
BaseRepresentation
bin11101001001111100101000…
…11001000101011010100011
322102000012001201012010211221
432210332110121011122203
531400413334401244024
6344205153031515511
716335021315620326
oct1644762431053243
9272005051163757
1064113466431139
1119479406402904
127235752228b97
1329a0b49088bb8
1411b917339a7bd
15762b121313e4
hex3a4f946456a3

64113466431139 has 2 divisors, whose sum is σ = 64113466431140. Its totient is φ = 64113466431138.

The previous prime is 64113466431127. The next prime is 64113466431211. The reversal of 64113466431139 is 93113466431146.

64113466431139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 64113466431139 - 231 = 64111318947491 is a prime.

It is a super-2 number, since 2×641134664311392 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (64113466431109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32056733215569 + 32056733215570.

It is an arithmetic number, because the mean of its divisors is an integer number (32056733215570).

Almost surely, 264113466431139 is an apocalyptic number.

64113466431139 is a deficient number, since it is larger than the sum of its proper divisors (1).

64113466431139 is an equidigital number, since it uses as much as digits as its factorization.

64113466431139 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3359232, while the sum is 52.

The spelling of 64113466431139 in words is "sixty-four trillion, one hundred thirteen billion, four hundred sixty-six million, four hundred thirty-one thousand, one hundred thirty-nine".