Base | Representation |
---|---|
bin | 101110101010000001000… |
… | …0001101000100001101111 |
3 | 211201000120120211012020102 |
4 | 1131110002001220201233 |
5 | 1320030114024434003 |
6 | 21345454122141315 |
7 | 1231165514665115 |
oct | 135240201504157 |
9 | 24630516735212 |
10 | 6412420155503 |
11 | 205254600847a |
12 | 87692a65183b |
13 | 3768c4bb037b |
14 | 1825116ddab5 |
15 | b1c05e47588 |
hex | 5d50206886f |
6412420155503 has 2 divisors, whose sum is σ = 6412420155504. Its totient is φ = 6412420155502.
The previous prime is 6412420155469. The next prime is 6412420155509. The reversal of 6412420155503 is 3055510242146.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6412420155503 - 26 = 6412420155439 is a prime.
It is a super-4 number, since 4×64124201555034 (a number of 52 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6412420155509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3206210077751 + 3206210077752.
It is an arithmetic number, because the mean of its divisors is an integer number (3206210077752).
Almost surely, 26412420155503 is an apocalyptic number.
6412420155503 is a deficient number, since it is larger than the sum of its proper divisors (1).
6412420155503 is an equidigital number, since it uses as much as digits as its factorization.
6412420155503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 6412420155503 its reverse (3055510242146), we get a palindrome (9467930397649).
The spelling of 6412420155503 in words is "six trillion, four hundred twelve billion, four hundred twenty million, one hundred fifty-five thousand, five hundred three".
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