6412498130133 has 24 divisors (see below), whose sum is σ = 9582216472920. Its totient is φ = 4127445987840.

The previous prime is 6412498130131. The next prime is 6412498130141. The reversal of 6412498130133 is 3310318942146.

6412498130133 is a `hidden beast` number, since 6 + 4 + 12 + 498 + 13 + 0 + 133 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 2792451549969 + 3620046580164 = 1671063^2 + 1902642^2 .

It is not a de Polignac number, because 6412498130133 - 2¹ = 6412498130131 is a prime.

It is a super-2 number, since 2×6412498130133² (a number of 26 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6412498130131) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7651185 + ... + 8447817.

It is an arithmetic number, because the mean of its divisors is an integer number (399259019705).

Almost surely, 2^{6412498130133} is an apocalyptic number.

It is an amenable number.

6412498130133 is a deficient number, since it is larger than the sum of its proper divisors (3169718342787).

6412498130133 is a wasteful number, since it uses less digits than its factorization.

6412498130133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 827509 (or 827506 counting only the distinct ones).

The product of its (nonzero) digits is 373248, while the sum is 45.

The spelling of 6412498130133 in words is "six trillion, four hundred twelve billion, four hundred ninety-eight million, one hundred thirty thousand, one hundred thirty-three".