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641299100173 is a prime number
BaseRepresentation
bin10010101010100000110…
…01111011001000001101
32021022022020101201101221
421111100121323020031
541001340032201143
61210335253203341
764221663260614
oct11252031731015
92238266351357
10641299100173
11227a78694846
12a4355930551
1348621bc12a4
14230791ba87b
1511a359182ed
hex955067b20d

641299100173 has 2 divisors, whose sum is σ = 641299100174. Its totient is φ = 641299100172.

The previous prime is 641299100159. The next prime is 641299100207. The reversal of 641299100173 is 371001992146.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 586775916169 + 54523184004 = 766013^2 + 233502^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-641299100173 is a prime.

It is a super-2 number, since 2×6412991001732 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (641299100873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320649550086 + 320649550087.

It is an arithmetic number, because the mean of its divisors is an integer number (320649550087).

Almost surely, 2641299100173 is an apocalyptic number.

It is an amenable number.

641299100173 is a deficient number, since it is larger than the sum of its proper divisors (1).

641299100173 is an equidigital number, since it uses as much as digits as its factorization.

641299100173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 43.

The spelling of 641299100173 in words is "six hundred forty-one billion, two hundred ninety-nine million, one hundred thousand, one hundred seventy-three".