Base | Representation |
---|---|
bin | 10010101010100001100… |
… | …10100000011011011101 |
3 | 2021022022200112010020111 |
4 | 21111100302200123131 |
5 | 41001343204410123 |
6 | 1210340043250021 |
7 | 64222102120522 |
oct | 11252062403335 |
9 | 2238280463214 |
10 | 641305544413 |
11 | 227a81296466 |
12 | a4357b19911 |
13 | 48623339551 |
14 | 23079db7149 |
15 | 11a3628c90d |
hex | 9550ca06dd |
641305544413 has 2 divisors, whose sum is σ = 641305544414. Its totient is φ = 641305544412.
The previous prime is 641305544357. The next prime is 641305544423. The reversal of 641305544413 is 314445503146.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 524961109764 + 116344434649 = 724542^2 + 341093^2 .
It is a cyclic number.
It is not a de Polignac number, because 641305544413 - 217 = 641305413341 is a prime.
It is a super-2 number, since 2×6413055444132 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (641305544423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320652772206 + 320652772207.
It is an arithmetic number, because the mean of its divisors is an integer number (320652772207).
Almost surely, 2641305544413 is an apocalyptic number.
It is an amenable number.
641305544413 is a deficient number, since it is larger than the sum of its proper divisors (1).
641305544413 is an equidigital number, since it uses as much as digits as its factorization.
641305544413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 40.
The spelling of 641305544413 in words is "six hundred forty-one billion, three hundred five million, five hundred forty-four thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.102 sec. • engine limits •