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64131443420503 is a prime number
BaseRepresentation
bin11101001010011110000111…
…11001110110110101010111
322102001220110120001211012211
432211033003321312311113
531401212144003424003
6344221324533054251
716336225644534124
oct1645170371666527
9272056416054184
1064131443420503
1119485aa09a9008
12723912a787387
1329a27525c0904
1411b9d9ab1774b
1576331549196d
hex3a53c3e76d57

64131443420503 has 2 divisors, whose sum is σ = 64131443420504. Its totient is φ = 64131443420502.

The previous prime is 64131443420491. The next prime is 64131443420531. The reversal of 64131443420503 is 30502434413146.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-64131443420503 is a prime.

It is a super-2 number, since 2×641314434205032 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (64131443420003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32065721710251 + 32065721710252.

It is an arithmetic number, because the mean of its divisors is an integer number (32065721710252).

Almost surely, 264131443420503 is an apocalyptic number.

64131443420503 is a deficient number, since it is larger than the sum of its proper divisors (1).

64131443420503 is an equidigital number, since it uses as much as digits as its factorization.

64131443420503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 414720, while the sum is 40.

Adding to 64131443420503 its reverse (30502434413146), we get a palindrome (94633877833649).

The spelling of 64131443420503 in words is "sixty-four trillion, one hundred thirty-one billion, four hundred forty-three million, four hundred twenty thousand, five hundred three".