Base | Representation |
---|---|
bin | 11101001010011110000111… |
… | …11001110110110101010111 |
3 | 22102001220110120001211012211 |
4 | 32211033003321312311113 |
5 | 31401212144003424003 |
6 | 344221324533054251 |
7 | 16336225644534124 |
oct | 1645170371666527 |
9 | 272056416054184 |
10 | 64131443420503 |
11 | 19485aa09a9008 |
12 | 723912a787387 |
13 | 29a27525c0904 |
14 | 11b9d9ab1774b |
15 | 76331549196d |
hex | 3a53c3e76d57 |
64131443420503 has 2 divisors, whose sum is σ = 64131443420504. Its totient is φ = 64131443420502.
The previous prime is 64131443420491. The next prime is 64131443420531. The reversal of 64131443420503 is 30502434413146.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-64131443420503 is a prime.
It is a super-2 number, since 2×641314434205032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64131443420003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32065721710251 + 32065721710252.
It is an arithmetic number, because the mean of its divisors is an integer number (32065721710252).
Almost surely, 264131443420503 is an apocalyptic number.
64131443420503 is a deficient number, since it is larger than the sum of its proper divisors (1).
64131443420503 is an equidigital number, since it uses as much as digits as its factorization.
64131443420503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 40.
Adding to 64131443420503 its reverse (30502434413146), we get a palindrome (94633877833649).
The spelling of 64131443420503 in words is "sixty-four trillion, one hundred thirty-one billion, four hundred forty-three million, four hundred twenty thousand, five hundred three".
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