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641320305213503 is a prime number
BaseRepresentation
bin1001000111010001110000010…
…0111110101100000000111111
310010002201121210202000100201102
42101310130010332230000333
51133024342441113313003
610151550251515403315
7252040602005424506
oct22164340476540077
93102647722010642
10641320305213503
1117638746111a693
125bb1820875353b
13216b0325b7b246
14b4520d594783d
154e2232d769588
hex2474704fac03f

641320305213503 has 2 divisors, whose sum is σ = 641320305213504. Its totient is φ = 641320305213502.

The previous prime is 641320305213493. The next prime is 641320305213517. The reversal of 641320305213503 is 305312503023146.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-641320305213503 is a prime.

It is a super-2 number, since 2×6413203052135032 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (641320305213803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320660152606751 + 320660152606752.

It is an arithmetic number, because the mean of its divisors is an integer number (320660152606752).

Almost surely, 2641320305213503 is an apocalyptic number.

641320305213503 is a deficient number, since it is larger than the sum of its proper divisors (1).

641320305213503 is an equidigital number, since it uses as much as digits as its factorization.

641320305213503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 38.

Adding to 641320305213503 its reverse (305312503023146), we get a palindrome (946632808236649).

The spelling of 641320305213503 in words is "six hundred forty-one trillion, three hundred twenty billion, three hundred five million, two hundred thirteen thousand, five hundred three".