Base | Representation |
---|---|
bin | 10010101010100111001… |
… | …10101010010111000011 |
3 | 2021022102222101110221202 |
4 | 21111103212222113003 |
5 | 41001442302133021 |
6 | 1210344451411415 |
7 | 64223214414431 |
oct | 11252346522703 |
9 | 2238388343852 |
10 | 641352771011 |
11 | 227aa5a12507 |
12 | a436b8b3b6b |
13 | 48630063494 |
14 | 2308238bd51 |
15 | 11a3a4baa0b |
hex | 95539aa5c3 |
641352771011 has 2 divisors, whose sum is σ = 641352771012. Its totient is φ = 641352771010.
The previous prime is 641352770999. The next prime is 641352771061. The reversal of 641352771011 is 110177253146.
It is a happy number.
641352771011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 641352771011 - 234 = 624172901827 is a prime.
It is a super-2 number, since 2×6413527710112 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (641352771061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320676385505 + 320676385506.
It is an arithmetic number, because the mean of its divisors is an integer number (320676385506).
Almost surely, 2641352771011 is an apocalyptic number.
641352771011 is a deficient number, since it is larger than the sum of its proper divisors (1).
641352771011 is an equidigital number, since it uses as much as digits as its factorization.
641352771011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 35280, while the sum is 38.
The spelling of 641352771011 in words is "six hundred forty-one billion, three hundred fifty-two million, seven hundred seventy-one thousand, eleven".
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