Base | Representation |
---|---|
bin | 111011101110110001… |
… | …100001001001000001 |
3 | 20010112201020222201222 |
4 | 323232301201021001 |
5 | 2022322142002403 |
6 | 45244034204425 |
7 | 4430223521021 |
oct | 735661411101 |
9 | 203481228658 |
10 | 64135500353 |
11 | 252218aa751 |
12 | 1051aa23715 |
13 | 6081471b12 |
14 | 3165bd9a81 |
15 | 1a05841338 |
hex | eeec61241 |
64135500353 has 2 divisors, whose sum is σ = 64135500354. Its totient is φ = 64135500352.
The previous prime is 64135500349. The next prime is 64135500409. The reversal of 64135500353 is 35300553146.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60707046544 + 3428453809 = 246388^2 + 58553^2 .
It is a cyclic number.
It is not a de Polignac number, because 64135500353 - 22 = 64135500349 is a prime.
It is a super-2 number, since 2×641355003532 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (64135500343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32067750176 + 32067750177.
It is an arithmetic number, because the mean of its divisors is an integer number (32067750177).
Almost surely, 264135500353 is an apocalyptic number.
It is an amenable number.
64135500353 is a deficient number, since it is larger than the sum of its proper divisors (1).
64135500353 is an equidigital number, since it uses as much as digits as its factorization.
64135500353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81000, while the sum is 35.
The spelling of 64135500353 in words is "sixty-four billion, one hundred thirty-five million, five hundred thousand, three hundred fifty-three".
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