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641710435625717 is a prime number
BaseRepresentation
bin1001000111101000011101101…
…0100100000110101011110101
310010011002220210121012201111212
42101322013122210012223311
51133102240433010010332
610152445412052211205
7252111022545262223
oct22172073244065365
93104086717181455
10641710435625717
1117651795a610667
125bb7b946609b05
132170b05a8303c3
14b466d45013b13
154e2c5639658b2
hex247a1da906af5

641710435625717 has 2 divisors, whose sum is σ = 641710435625718. Its totient is φ = 641710435625716.

The previous prime is 641710435625681. The next prime is 641710435625731. The reversal of 641710435625717 is 717526534017146.

641710435625717 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 615975116771716 + 25735318854001 = 24818846^2 + 5072999^2 .

It is a cyclic number.

It is not a de Polignac number, because 641710435625717 - 210 = 641710435624693 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (641710435625417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320855217812858 + 320855217812859.

It is an arithmetic number, because the mean of its divisors is an integer number (320855217812859).

Almost surely, 2641710435625717 is an apocalyptic number.

It is an amenable number.

641710435625717 is a deficient number, since it is larger than the sum of its proper divisors (1).

641710435625717 is an equidigital number, since it uses as much as digits as its factorization.

641710435625717 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 29635200, while the sum is 59.

The spelling of 641710435625717 in words is "six hundred forty-one trillion, seven hundred ten billion, four hundred thirty-five million, six hundred twenty-five thousand, seven hundred seventeen".