Base | Representation |
---|---|
bin | 101110101110011010111… |
… | …1000011100011001110111 |
3 | 211201220222212100222111212 |
4 | 1131130311320130121313 |
5 | 1320204002301041000 |
6 | 21354100533352035 |
7 | 1231652114110502 |
oct | 135346570343167 |
9 | 24656885328455 |
10 | 6421880096375 |
11 | 205655a995027 |
12 | 87872a79861b |
13 | 377771a2b013 |
14 | 182b6bc40139 |
15 | b20ab6c7c35 |
hex | 5d735e1c677 |
6421880096375 has 16 divisors (see below), whose sum is σ = 8026779825792. Its totient is φ = 5129636471200.
The previous prime is 6421880096327. The next prime is 6421880096389. The reversal of 6421880096375 is 5736900881246.
It is not a de Polignac number, because 6421880096375 - 214 = 6421880079991 is a prime.
It is a super-3 number, since 3×64218800963753 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39256079 + ... + 39419328.
It is an arithmetic number, because the mean of its divisors is an integer number (501673739112).
It is a 2-persistent number, because it is pandigital, and so is 2⋅6421880096375 = 12843760192750, but 3⋅6421880096375 = 19265640289125 is not.
Almost surely, 26421880096375 is an apocalyptic number.
6421880096375 is a deficient number, since it is larger than the sum of its proper divisors (1604899729417).
6421880096375 is an equidigital number, since it uses as much as digits as its factorization.
6421880096375 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78676075 (or 78676065 counting only the distinct ones).
The product of its (nonzero) digits is 17418240, while the sum is 59.
The spelling of 6421880096375 in words is "six trillion, four hundred twenty-one billion, eight hundred eighty million, ninety-six thousand, three hundred seventy-five".
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