Base | Representation |
---|---|
bin | 101110101110011110110… |
… | …1111101100010011100001 |
3 | 211201221100001121101121201 |
4 | 1131130331233230103201 |
5 | 1320204240034114222 |
6 | 21354122005121201 |
7 | 1231655305332343 |
oct | 135347557542341 |
9 | 24657301541551 |
10 | 6422012019937 |
11 | 2056618400168 |
12 | 8787669b9201 |
13 | 37779316b1b7 |
14 | 182b81581293 |
15 | b20b8086427 |
hex | 5d73dbec4e1 |
6422012019937 has 2 divisors, whose sum is σ = 6422012019938. Its totient is φ = 6422012019936.
The previous prime is 6422012019931. The next prime is 6422012020013. The reversal of 6422012019937 is 7399102102246.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4001744190096 + 2420267829841 = 2000436^2 + 1555721^2 .
It is a cyclic number.
It is not a de Polignac number, because 6422012019937 - 27 = 6422012019809 is a prime.
It is not a weakly prime, because it can be changed into another prime (6422012019931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3211006009968 + 3211006009969.
It is an arithmetic number, because the mean of its divisors is an integer number (3211006009969).
Almost surely, 26422012019937 is an apocalyptic number.
It is an amenable number.
6422012019937 is a deficient number, since it is larger than the sum of its proper divisors (1).
6422012019937 is an equidigital number, since it uses as much as digits as its factorization.
6422012019937 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 326592, while the sum is 46.
The spelling of 6422012019937 in words is "six trillion, four hundred twenty-two billion, twelve million, nineteen thousand, nine hundred thirty-seven".
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