Base | Representation |
---|---|
bin | 101110101110011110110… |
… | …1111101100010011100010 |
3 | 211201221100001121101121202 |
4 | 1131130331233230103202 |
5 | 1320204240034114223 |
6 | 21354122005121202 |
7 | 1231655305332344 |
oct | 135347557542342 |
9 | 24657301541552 |
10 | 6422012019938 |
11 | 2056618400169 |
12 | 8787669b9202 |
13 | 37779316b1b8 |
14 | 182b81581294 |
15 | b20b8086428 |
hex | 5d73dbec4e2 |
6422012019938 has 8 divisors (see below), whose sum is σ = 9633084637932. Its totient is φ = 3210983807296.
The previous prime is 6422012019937. The next prime is 6422012020013. The reversal of 6422012019938 is 8399102102246.
It is a happy number.
It can be written as a sum of positive squares in 2 ways, for example, as 5636479012129 + 785533007809 = 2374127^2 + 886303^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 6422012019892 and 6422012019901.
It is not an unprimeable number, because it can be changed into a prime (6422012019931) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10737395 + ... + 11319702.
Almost surely, 26422012019938 is an apocalyptic number.
6422012019938 is a deficient number, since it is larger than the sum of its proper divisors (3211072617994).
6422012019938 is a wasteful number, since it uses less digits than its factorization.
6422012019938 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22202676.
The product of its (nonzero) digits is 373248, while the sum is 47.
The spelling of 6422012019938 in words is "six trillion, four hundred twenty-two billion, twelve million, nineteen thousand, nine hundred thirty-eight".
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