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642437113750 = 254513949691
BaseRepresentation
bin10010101100101000011…
…11000110011110010110
32021102020112202210112221
421112110033012132112
541011202400120000
61211044224532554
764262122236505
oct11262417063626
92242215683487
10642437113750
11228502003233
12a4612a8115a
13487738c15c3
14231463b283c
1511aa07ac61a
hex95943c6796

642437113750 has 20 divisors (see below), whose sum is σ = 1204184128356. Its totient is φ = 256974845000.

The previous prime is 642437113741. The next prime is 642437113751. The reversal of 642437113750 is 57311734246.

642437113750 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 642437113697 and 642437113706.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (642437113751) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 256973596 + ... + 256976095.

Almost surely, 2642437113750 is an apocalyptic number.

642437113750 is a deficient number, since it is larger than the sum of its proper divisors (561747014606).

642437113750 is an equidigital number, since it uses as much as digits as its factorization.

642437113750 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 513949713 (or 513949698 counting only the distinct ones).

The product of its (nonzero) digits is 423360, while the sum is 43.

Adding to 642437113750 its reverse (57311734246), we get a palindrome (699748847996).

The spelling of 642437113750 in words is "six hundred forty-two billion, four hundred thirty-seven million, one hundred thirteen thousand, seven hundred fifty".

Divisors: 1 2 5 10 25 50 125 250 625 1250 513949691 1027899382 2569748455 5139496910 12848742275 25697484550 64243711375 128487422750 321218556875 642437113750