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64267314640441 = 115842483149131
BaseRepresentation
bin11101001110011011001100…
…11101011011011000111001
322102112220011122201221110221
432213031212131123120321
531410423430021443231
6344403555144540041
716352105653046563
oct1647154635333071
9272486148657427
1064267314640441
111952868473a620
12725b529781621
1329b24c6981a83
1411c27a9c6c333
15766b189a0d11
hex3a736675b639

64267314640441 has 4 divisors (see below), whose sum is σ = 70109797789584. Its totient is φ = 58424831491300.

The previous prime is 64267314640393. The next prime is 64267314640523. The reversal of 64267314640441 is 14404641376246.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 64267314640441 - 211 = 64267314638393 is a prime.

It is a super-2 number, since 2×642673146404412 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (64267314640741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2921241574555 + ... + 2921241574576.

It is an arithmetic number, because the mean of its divisors is an integer number (17527449447396).

Almost surely, 264267314640441 is an apocalyptic number.

It is an amenable number.

64267314640441 is a deficient number, since it is larger than the sum of its proper divisors (5842483149143).

64267314640441 is a wasteful number, since it uses less digits than its factorization.

64267314640441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5842483149142.

The product of its (nonzero) digits is 9289728, while the sum is 52.

The spelling of 64267314640441 in words is "sixty-four trillion, two hundred sixty-seven billion, three hundred fourteen million, six hundred forty thousand, four hundred forty-one".

Divisors: 1 11 5842483149131 64267314640441