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64306211101997 is a prime number
BaseRepresentation
bin11101001111100011101001…
…10111101001110100101101
322102200121120102021220211012
432213301310313221310231
531412043110020230442
6344433510543035005
716354653600366254
oct1647616467516455
9272617512256735
1064306211101997
1119543124786917
127266b83b9ba65
1329b6085214bb7
1411c4619a5979b
15767b43653582
hex3a7c74de9d2d

64306211101997 has 2 divisors, whose sum is σ = 64306211101998. Its totient is φ = 64306211101996.

The previous prime is 64306211101987. The next prime is 64306211102053. The reversal of 64306211101997 is 79910111260346.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50078423245321 + 14227787856676 = 7076611^2 + 3771974^2 .

It is a cyclic number.

It is not a de Polignac number, because 64306211101997 - 218 = 64306210839853 is a prime.

It is a super-4 number, since 4×643062111019974 (a number of 56 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (64306211101927) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32153105550998 + 32153105550999.

It is an arithmetic number, because the mean of its divisors is an integer number (32153105550999).

Almost surely, 264306211101997 is an apocalyptic number.

It is an amenable number.

64306211101997 is a deficient number, since it is larger than the sum of its proper divisors (1).

64306211101997 is an equidigital number, since it uses as much as digits as its factorization.

64306211101997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 489888, while the sum is 50.

The spelling of 64306211101997 in words is "sixty-four trillion, three hundred six billion, two hundred eleven million, one hundred one thousand, nine hundred ninety-seven".