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64311497 is a prime number
BaseRepresentation
bin1111010101010…
…1000011001001
311111000100210022
43311111003021
5112430431442
610214230225
71410432035
oct365250311
9144010708
1064311497
11333361a8
1219655375
1310429553
1487811c5
1559a53d2
hex3d550c9

64311497 has 2 divisors, whose sum is σ = 64311498. Its totient is φ = 64311496.

The previous prime is 64311479. The next prime is 64311517. The reversal of 64311497 is 79411346.

64311497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (64311479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 56715961 + 7595536 = 7531^2 + 2756^2 .

It is a cyclic number.

It is not a de Polignac number, because 64311497 - 26 = 64311433 is a prime.

It is not a weakly prime, because it can be changed into another prime (64311397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32155748 + 32155749.

It is an arithmetic number, because the mean of its divisors is an integer number (32155749).

Almost surely, 264311497 is an apocalyptic number.

It is an amenable number.

64311497 is a deficient number, since it is larger than the sum of its proper divisors (1).

64311497 is an equidigital number, since it uses as much as digits as its factorization.

64311497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18144, while the sum is 35.

The square root of 64311497 is about 8019.4449309164. Note that the first 3 decimals coincide. The cubic root of 64311497 is about 400.6479020740.

The spelling of 64311497 in words is "sixty-four million, three hundred eleven thousand, four hundred ninety-seven".