Base | Representation |
---|---|
bin | 111011111011000110… |
… | …111001111010111111 |
3 | 20011002010122021121112 |
4 | 323323012321322333 |
5 | 2023233130332341 |
6 | 45320345352235 |
7 | 4435315442411 |
oct | 737306717277 |
9 | 204063567545 |
10 | 64342433471 |
11 | 25318698658 |
12 | 1057819867b |
13 | 60b52b5a54 |
14 | 31854a49b1 |
15 | 1a18ab9aeb |
hex | efb1b9ebf |
64342433471 has 2 divisors, whose sum is σ = 64342433472. Its totient is φ = 64342433470.
The previous prime is 64342433443. The next prime is 64342433479. The reversal of 64342433471 is 17433424346.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-64342433471 is a prime.
It is a super-3 number, since 3×643424334713 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64342433479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32171216735 + 32171216736.
It is an arithmetic number, because the mean of its divisors is an integer number (32171216736).
Almost surely, 264342433471 is an apocalyptic number.
64342433471 is a deficient number, since it is larger than the sum of its proper divisors (1).
64342433471 is an equidigital number, since it uses as much as digits as its factorization.
64342433471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 580608, while the sum is 41.
The spelling of 64342433471 in words is "sixty-four billion, three hundred forty-two million, four hundred thirty-three thousand, four hundred seventy-one".
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