Base | Representation |
---|---|
bin | 11101010000101000001101… |
… | …00011111010110001000111 |
3 | 22102211010120100120210020111 |
4 | 32220110012203322301013 |
5 | 31413143443333443143 |
6 | 344502434553213451 |
7 | 16360425616506655 |
oct | 1650240643726107 |
9 | 272733510523214 |
10 | 64343015140423 |
11 | 195577a069a6a8 |
12 | 7272135701287 |
13 | 29b969c110b26 |
14 | 11c630b9addd5 |
15 | 768a9978899d |
hex | 3a85068fac47 |
64343015140423 has 2 divisors, whose sum is σ = 64343015140424. Its totient is φ = 64343015140422.
The previous prime is 64343015140277. The next prime is 64343015140451. The reversal of 64343015140423 is 32404151034346.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-64343015140423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64343015140483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32171507570211 + 32171507570212.
It is an arithmetic number, because the mean of its divisors is an integer number (32171507570212).
Almost surely, 264343015140423 is an apocalyptic number.
64343015140423 is a deficient number, since it is larger than the sum of its proper divisors (1).
64343015140423 is an equidigital number, since it uses as much as digits as its factorization.
64343015140423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 40.
Adding to 64343015140423 its reverse (32404151034346), we get a palindrome (96747166174769).
The spelling of 64343015140423 in words is "sixty-four trillion, three hundred forty-three billion, fifteen million, one hundred forty thousand, four hundred twenty-three".
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