Search a number
-
+
64352000131 is a prime number
BaseRepresentation
bin111011111011101011…
…011001100010000011
320011002210122022121021
4323323223121202003
52023243103001011
645321330410311
74435462655506
oct737353314203
9204083568537
1064352000131
1125323032191
121057b430997
1360b72852b3
14318687513d
151a19859471
hexefbad9883

64352000131 has 2 divisors, whose sum is σ = 64352000132. Its totient is φ = 64352000130.

The previous prime is 64352000099. The next prime is 64352000143. The reversal of 64352000131 is 13100025346.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 64352000131 - 25 = 64352000099 is a prime.

It is a super-2 number, since 2×643520001312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 64352000096 and 64352000105.

It is not a weakly prime, because it can be changed into another prime (64352010131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32176000065 + 32176000066.

It is an arithmetic number, because the mean of its divisors is an integer number (32176000066).

Almost surely, 264352000131 is an apocalyptic number.

64352000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

64352000131 is an equidigital number, since it uses as much as digits as its factorization.

64352000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 64352000131 its reverse (13100025346), we get a palindrome (77452025477).

The spelling of 64352000131 in words is "sixty-four billion, three hundred fifty-two million, one hundred thirty-one", and thus it is an aban number.