Base | Representation |
---|---|
bin | 1011111111110001… |
… | …00000000100010101 |
3 | 121121211220112200201 |
4 | 11333320200010111 |
5 | 101142231011031 |
6 | 2543025540501 |
7 | 315413135416 |
oct | 57770400425 |
9 | 17554815621 |
10 | 6440485141 |
11 | 28055388a2 |
12 | 12b8aa4731 |
13 | 7b841396c |
14 | 45151180d |
15 | 27a646d61 |
hex | 17fe20115 |
6440485141 has 2 divisors, whose sum is σ = 6440485142. Its totient is φ = 6440485140.
The previous prime is 6440485127. The next prime is 6440485147. The reversal of 6440485141 is 1415840446.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4533328900 + 1907156241 = 67330^2 + 43671^2 .
It is a cyclic number.
It is not a de Polignac number, because 6440485141 - 25 = 6440485109 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6440485141.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6440485147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3220242570 + 3220242571.
It is an arithmetic number, because the mean of its divisors is an integer number (3220242571).
Almost surely, 26440485141 is an apocalyptic number.
It is an amenable number.
6440485141 is a deficient number, since it is larger than the sum of its proper divisors (1).
6440485141 is an equidigital number, since it uses as much as digits as its factorization.
6440485141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61440, while the sum is 37.
The square root of 6440485141 is about 80252.6332340566. The cubic root of 6440485141 is about 1860.5422110803.
The spelling of 6440485141 in words is "six billion, four hundred forty million, four hundred eighty-five thousand, one hundred forty-one".
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