Base | Representation |
---|---|
bin | 101110111101001110101… |
… | …1000001010000001100111 |
3 | 211211222002010211011020202 |
4 | 1131322131120022001213 |
5 | 1321214114343442043 |
6 | 21420440310221115 |
7 | 1234156144242512 |
oct | 135723530120147 |
9 | 24758063734222 |
10 | 6453681234023 |
11 | 2068a9989a471 |
12 | 88292495479b |
13 | 37a76c2c0c2a |
14 | 184507579d79 |
15 | b2d1d4d21b8 |
hex | 5de9d60a067 |
6453681234023 has 2 divisors, whose sum is σ = 6453681234024. Its totient is φ = 6453681234022.
The previous prime is 6453681233891. The next prime is 6453681234041. The reversal of 6453681234023 is 3204321863546.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6453681234023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6453681234073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3226840617011 + 3226840617012.
It is an arithmetic number, because the mean of its divisors is an integer number (3226840617012).
Almost surely, 26453681234023 is an apocalyptic number.
6453681234023 is a deficient number, since it is larger than the sum of its proper divisors (1).
6453681234023 is an equidigital number, since it uses as much as digits as its factorization.
6453681234023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2488320, while the sum is 47.
The spelling of 6453681234023 in words is "six trillion, four hundred fifty-three billion, six hundred eighty-one million, two hundred thirty-four thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •