6453719413 has 18 divisors (see below), whose sum is σ = 6796355138. Its totient is φ = 6123821760.

The previous prime is 6453719369. The next prime is 6453719453. The reversal of 6453719413 is 3149173546.

It can be written as a sum of positive squares in 3 ways, for example, as 3320294884 + 3133424529 = 57622^2 + 55977^2 .

It is not a de Polignac number, because 6453719413 - 2¹³ = 6453711221 is a prime.

It is a super-3 number, since 3×6453719413³ (a number of 30 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 6453719413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6453719453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 22966833 + ... + 22967113.

Almost surely, 2^6453719413 is an apocalyptic number.

It is an amenable number.

6453719413 is a deficient number, since it is larger than the sum of its proper divisors (342635725).

6453719413 is an frugal number, since it uses more digits than its factorization.

6453719413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 693 (or 365 counting only the distinct ones).

The product of its digits is 272160, while the sum is 43.

The square root of 6453719413 is about 80335.0447376486. The cubic root of 6453719413 is about 1861.8157215305.

The spelling of 6453719413 in words is "six billion, four hundred fifty-three million, seven hundred nineteen thousand, four hundred thirteen".