Base | Representation |
---|---|
bin | 101110111101100111010… |
… | …1101100001101011000101 |
3 | 211212001012211020221021011 |
4 | 1131323032231201223011 |
5 | 1321222313240410433 |
6 | 21421054354322221 |
7 | 1234215514404625 |
oct | 135731655415305 |
9 | 24761184227234 |
10 | 6454508919493 |
11 | 206938401a848 |
12 | 882b15b89371 |
13 | 37a87191844b |
14 | 184585470885 |
15 | b2d6aec73cd |
hex | 5deceb61ac5 |
6454508919493 has 2 divisors, whose sum is σ = 6454508919494. Its totient is φ = 6454508919492.
The previous prime is 6454508919479. The next prime is 6454508919511. The reversal of 6454508919493 is 3949198054546.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3790193772964 + 2664315146529 = 1946842^2 + 1632273^2 .
It is a cyclic number.
It is not a de Polignac number, because 6454508919493 - 225 = 6454475365061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6454505919493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3227254459746 + 3227254459747.
It is an arithmetic number, because the mean of its divisors is an integer number (3227254459747).
Almost surely, 26454508919493 is an apocalyptic number.
It is an amenable number.
6454508919493 is a deficient number, since it is larger than the sum of its proper divisors (1).
6454508919493 is an equidigital number, since it uses as much as digits as its factorization.
6454508919493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 167961600, while the sum is 67.
The spelling of 6454508919493 in words is "six trillion, four hundred fifty-four billion, five hundred eight million, nine hundred nineteen thousand, four hundred ninety-three".
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