Base | Representation |
---|---|
bin | 11101011011101100111111… |
… | …01010100010101111110001 |
3 | 22111011111202211221220120001 |
4 | 32231312133222202233301 |
5 | 31440412302433210022 |
6 | 345353330105150001 |
7 | 16430056452302101 |
oct | 1655663752425761 |
9 | 274144684856501 |
10 | 64723540913137 |
11 | 19694110562887 |
12 | 7313a32a8b301 |
13 | 2a16532c81452 |
14 | 11da8c9631201 |
15 | 77391b670b27 |
hex | 3add9faa2bf1 |
64723540913137 has 12 divisors (see below), whose sum is σ = 68312681896080. Its totient is φ = 61314032353752.
The previous prime is 64723540913069. The next prime is 64723540913147. The reversal of 64723540913137 is 73131904532746.
It is a de Polignac number, because none of the positive numbers 2k-64723540913137 is a prime.
It is not an unprimeable number, because it can be changed into a prime (64723540913147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2994814 + ... + 11765032.
It is an arithmetic number, because the mean of its divisors is an integer number (5692723491340).
Almost surely, 264723540913137 is an apocalyptic number.
It is an amenable number.
64723540913137 is a deficient number, since it is larger than the sum of its proper divisors (3589140982943).
64723540913137 is a wasteful number, since it uses less digits than its factorization.
64723540913137 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8790700 (or 8790681 counting only the distinct ones).
The product of its (nonzero) digits is 11430720, while the sum is 55.
The spelling of 64723540913137 in words is "sixty-four trillion, seven hundred twenty-three billion, five hundred forty million, nine hundred thirteen thousand, one hundred thirty-seven".
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