Base | Representation |
---|---|
bin | 111100010011010100… |
… | …001010110110111111 |
3 | 20012010102211211211101 |
4 | 330103110022312333 |
5 | 2030101113021103 |
6 | 45424534233531 |
7 | 4451346466222 |
oct | 742324126677 |
9 | 205112754741 |
10 | 64748563903 |
11 | 25506970441 |
12 | 106701b58a7 |
13 | 614b49280a |
14 | 31c33c35b9 |
15 | 1a3e58ea1d |
hex | f1350adbf |
64748563903 has 2 divisors, whose sum is σ = 64748563904. Its totient is φ = 64748563902.
The previous prime is 64748563877. The next prime is 64748563921. The reversal of 64748563903 is 30936584746.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 64748563903 - 221 = 64746466751 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64748563963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32374281951 + 32374281952.
It is an arithmetic number, because the mean of its divisors is an integer number (32374281952).
Almost surely, 264748563903 is an apocalyptic number.
64748563903 is a deficient number, since it is larger than the sum of its proper divisors (1).
64748563903 is an equidigital number, since it uses as much as digits as its factorization.
64748563903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13063680, while the sum is 55.
The spelling of 64748563903 in words is "sixty-four billion, seven hundred forty-eight million, five hundred sixty-three thousand, nine hundred three".
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