Base | Representation |
---|---|
bin | 11101100111000010100000… |
… | …10010011111111011110011 |
3 | 22112112202011111100100222110 |
4 | 32303201100102133323303 |
5 | 32013303012103442120 |
6 | 350252304531140403 |
7 | 16500156052351230 |
oct | 1663412022377363 |
9 | 275482144310873 |
10 | 65113051234035 |
11 | 19824320a22aa2 |
12 | 7377419144703 |
13 | 2a44199321b7c |
14 | 12116ba604787 |
15 | 77db171d12e0 |
hex | 3b385049fef3 |
65113051234035 has 128 divisors (see below), whose sum is σ = 128287236188160. Its totient is φ = 27522393440256.
The previous prime is 65113051234009. The next prime is 65113051234037. The reversal of 65113051234035 is 53043215031156.
It is not a de Polignac number, because 65113051234035 - 212 = 65113051229939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 65113051233984 and 65113051234002.
It is not an unprimeable number, because it can be changed into a prime (65113051234037) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 163355139 + ... + 163753251.
It is an arithmetic number, because the mean of its divisors is an integer number (1002244032720).
Almost surely, 265113051234035 is an apocalyptic number.
65113051234035 is a deficient number, since it is larger than the sum of its proper divisors (63174184954125).
65113051234035 is a wasteful number, since it uses less digits than its factorization.
65113051234035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 399757.
The product of its (nonzero) digits is 162000, while the sum is 39.
The spelling of 65113051234035 in words is "sixty-five trillion, one hundred thirteen billion, fifty-one million, two hundred thirty-four thousand, thirty-five".
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