65130403147 has 4 divisors (see below), whose sum is σ = 66198114736. Its totient is φ = 64062691560.

The previous prime is 65130403141. The next prime is 65130403153. The reversal of 65130403147 is 74130403156.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (65130403141) and next prime (65130403153).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-65130403147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (65130403141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 533855703 + ... + 533855824.

It is an arithmetic number, because the mean of its divisors is an integer number (16549528684).

Almost surely, 2^65130403147 is an apocalyptic number.

65130403147 is a deficient number, since it is larger than the sum of its proper divisors (1067711589).

65130403147 is a wasteful number, since it uses less digits than its factorization.

65130403147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1067711588.

The product of its (nonzero) digits is 30240, while the sum is 34.

Subtracting 65130403147 from its reverse (74130403156), we obtain a palindrome (9000000009).

The spelling of 65130403147 in words is "sixty-five billion, one hundred thirty million, four hundred three thousand, one hundred forty-seven".