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65143386551 = 353318438547
BaseRepresentation
bin111100101010110110…
…010011000110110111
320020010221202220200102
4330222312103012313
52031403201332201
645532040504315
74464212435525
oct745266230667
9206127686612
1065143386551
112569981a551
121076047b09b
1361b2210699
14321d9db315
151a6407e26b
hexf2ad931b7

65143386551 has 4 divisors (see below), whose sum is σ = 65161828632. Its totient is φ = 65124944472.

The previous prime is 65143386467. The next prime is 65143386559. The reversal of 65143386551 is 15568334156.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 65143386551 - 226 = 65076277687 is a prime.

It is a super-2 number, since 2×651433865512 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 65143386496 and 65143386505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (65143386559) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9215741 + ... + 9222806.

It is an arithmetic number, because the mean of its divisors is an integer number (16290457158).

Almost surely, 265143386551 is an apocalyptic number.

65143386551 is a deficient number, since it is larger than the sum of its proper divisors (18442081).

65143386551 is a wasteful number, since it uses less digits than its factorization.

65143386551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18442080.

The product of its digits is 1296000, while the sum is 47.

The spelling of 65143386551 in words is "sixty-five billion, one hundred forty-three million, three hundred eighty-six thousand, five hundred fifty-one".

Divisors: 1 3533 18438547 65143386551