Base | Representation |
---|---|
bin | 111100101010111010… |
… | …010110110011000011 |
3 | 20020011000202221210102 |
4 | 330222322112303003 |
5 | 2031403434401433 |
6 | 45532115353015 |
7 | 4464224455625 |
oct | 745272266303 |
9 | 206130687712 |
10 | 65144450243 |
11 | 2569a386734 |
12 | 107608b276b |
13 | 61b24c38a2 |
14 | 321dbd6c15 |
15 | 1a641de4e8 |
hex | f2ae96cc3 |
65144450243 has 2 divisors, whose sum is σ = 65144450244. Its totient is φ = 65144450242.
The previous prime is 65144450221. The next prime is 65144450281. The reversal of 65144450243 is 34205444156.
It is an a-pointer prime, because the next prime (65144450281) can be obtained adding 65144450243 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 65144450243 - 218 = 65144188099 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 65144450197 and 65144450206.
It is not a weakly prime, because it can be changed into another prime (65144450543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32572225121 + 32572225122.
It is an arithmetic number, because the mean of its divisors is an integer number (32572225122).
Almost surely, 265144450243 is an apocalyptic number.
65144450243 is a deficient number, since it is larger than the sum of its proper divisors (1).
65144450243 is an equidigital number, since it uses as much as digits as its factorization.
65144450243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 230400, while the sum is 38.
Adding to 65144450243 its reverse (34205444156), we get a palindrome (99349894399).
The spelling of 65144450243 in words is "sixty-five billion, one hundred forty-four million, four hundred fifty thousand, two hundred forty-three".
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