Base | Representation |
---|---|
bin | 1001010010000010000010111… |
… | …1100001101100101010001101 |
3 | 10011122121001120111211110022011 |
4 | 2110200200233201230222031 |
5 | 1141102112042341001031 |
6 | 10233042411122221221 |
7 | 254401113363626446 |
oct | 22440405741545215 |
9 | 3148531514743264 |
10 | 653145064000141 |
11 | 17a1262a2198129 |
12 | 61307a804b4811 |
13 | 2205a4137cac6b |
14 | b74056575c2cd |
15 | 5079c06b3c6b1 |
hex | 252082f86ca8d |
653145064000141 has 32 divisors (see below), whose sum is σ = 693834921964800. Its totient is φ = 613610827315200.
The previous prime is 653145064000127. The next prime is 653145064000153. The reversal of 653145064000141 is 141000460541356.
It is not a de Polignac number, because 653145064000141 - 25 = 653145064000109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 653145064000094 and 653145064000103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (653145064100141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 112100541 + ... + 117782941.
It is an arithmetic number, because the mean of its divisors is an integer number (21682341311400).
Almost surely, 2653145064000141 is an apocalyptic number.
It is an amenable number.
653145064000141 is a deficient number, since it is larger than the sum of its proper divisors (40689857964659).
653145064000141 is a wasteful number, since it uses less digits than its factorization.
653145064000141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5682949.
The product of its (nonzero) digits is 172800, while the sum is 40.
The spelling of 653145064000141 in words is "six hundred fifty-three trillion, one hundred forty-five billion, sixty-four million, one hundred forty-one", and thus it is an aban number.
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