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65317703421437 is a prime number
BaseRepresentation
bin11101101100111111101101…
…00000101000110111111101
322120021022102001112122211222
432312133312200220313331
532030131124033441222
6350530312205523125
716521022403265635
oct1666376640506775
9276238361478758
1065317703421437
11198a309a830475
1273ab0128734a5
132a5a58240124c
14121b5724c96c5
157840e3ca6542
hex3b67f6828dfd

65317703421437 has 2 divisors, whose sum is σ = 65317703421438. Its totient is φ = 65317703421436.

The previous prime is 65317703421343. The next prime is 65317703421479. The reversal of 65317703421437 is 73412430771356.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43213610574436 + 22104092847001 = 6573706^2 + 4701499^2 .

It is a cyclic number.

It is not a de Polignac number, because 65317703421437 - 232 = 65313408454141 is a prime.

It is a super-2 number, since 2×653177034214372 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (65317703421637) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32658851710718 + 32658851710719.

It is an arithmetic number, because the mean of its divisors is an integer number (32658851710719).

Almost surely, 265317703421437 is an apocalyptic number.

It is an amenable number.

65317703421437 is a deficient number, since it is larger than the sum of its proper divisors (1).

65317703421437 is an equidigital number, since it uses as much as digits as its factorization.

65317703421437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8890560, while the sum is 53.

The spelling of 65317703421437 in words is "sixty-five trillion, three hundred seventeen billion, seven hundred three million, four hundred twenty-one thousand, four hundred thirty-seven".