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65365116980437 is a prime number
BaseRepresentation
bin11101101110011000000001…
…00101000000110011010101
322120102211210101112000102201
432313030000211000303111
532031420224421333222
6351004153055004501
716524321351012241
oct1667140045006325
9276384711460381
1065365116980437
111991121051a07a
1273b8245509731
132a61b9a3677c1
14121d98d507421
1578546b548427
hex3b7300940cd5

65365116980437 has 2 divisors, whose sum is σ = 65365116980438. Its totient is φ = 65365116980436.

The previous prime is 65365116980353. The next prime is 65365116980507. The reversal of 65365116980437 is 73408961156356.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60868176861636 + 4496940118801 = 7801806^2 + 2120599^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-65365116980437 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (65365116980237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32682558490218 + 32682558490219.

It is an arithmetic number, because the mean of its divisors is an integer number (32682558490219).

Almost surely, 265365116980437 is an apocalyptic number.

It is an amenable number.

65365116980437 is a deficient number, since it is larger than the sum of its proper divisors (1).

65365116980437 is an equidigital number, since it uses as much as digits as its factorization.

65365116980437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97977600, while the sum is 64.

The spelling of 65365116980437 in words is "sixty-five trillion, three hundred sixty-five billion, one hundred sixteen million, nine hundred eighty thousand, four hundred thirty-seven".