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65432592131 is a prime number
BaseRepresentation
bin111100111100000101…
…100001111100000011
320020220002222002011012
4330330011201330003
52033001220422011
650020451311135
74504323566504
oct747405417403
9206802862135
1065432592131
1125827aa0a25
12108212ab4ab
13622a0cc14a
14324a1a0bab
151a7e659a8b
hexf3c161f03

65432592131 has 2 divisors, whose sum is σ = 65432592132. Its totient is φ = 65432592130.

The previous prime is 65432592101. The next prime is 65432592133. The reversal of 65432592131 is 13129523456.

65432592131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 65432592131 - 26 = 65432592067 is a prime.

It is a super-2 number, since 2×654325921312 (a number of 22 digits) contains 22 as substring.

Together with 65432592133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (65432592133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32716296065 + 32716296066.

It is an arithmetic number, because the mean of its divisors is an integer number (32716296066).

Almost surely, 265432592131 is an apocalyptic number.

65432592131 is a deficient number, since it is larger than the sum of its proper divisors (1).

65432592131 is an equidigital number, since it uses as much as digits as its factorization.

65432592131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 194400, while the sum is 41.

The spelling of 65432592131 in words is "sixty-five billion, four hundred thirty-two million, five hundred ninety-two thousand, one hundred thirty-one".