Base | Representation |
---|---|
bin | 101111100111010110101… |
… | …0001010111000100110101 |
3 | 212011121120112002102101022 |
4 | 1133032231101113010311 |
5 | 1324204400400414031 |
6 | 21530200514510525 |
7 | 1243540641623516 |
oct | 137165521270465 |
9 | 25147515072338 |
10 | 6544142201141 |
11 | 20a339a737a16 |
12 | 89836bb95445 |
13 | 38615777c9cc |
14 | 188a4978ca0d |
15 | b536506697b |
hex | 5f3ad457135 |
6544142201141 has 2 divisors, whose sum is σ = 6544142201142. Its totient is φ = 6544142201140.
The previous prime is 6544142201057. The next prime is 6544142201167. The reversal of 6544142201141 is 1411022414456.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3339558882916 + 3204583318225 = 1827446^2 + 1790135^2 .
It is a cyclic number.
It is not a de Polignac number, because 6544142201141 - 214 = 6544142184757 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6544142201171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3272071100570 + 3272071100571.
It is an arithmetic number, because the mean of its divisors is an integer number (3272071100571).
Almost surely, 26544142201141 is an apocalyptic number.
It is an amenable number.
6544142201141 is a deficient number, since it is larger than the sum of its proper divisors (1).
6544142201141 is an equidigital number, since it uses as much as digits as its factorization.
6544142201141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30720, while the sum is 35.
Adding to 6544142201141 its reverse (1411022414456), we get a palindrome (7955164615597).
The spelling of 6544142201141 in words is "six trillion, five hundred forty-four billion, one hundred forty-two million, two hundred one thousand, one hundred forty-one".
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