65513405473 has 4 divisors (see below), whose sum is σ = 65513931028. Its totient is φ = 65512879920.

The previous prime is 65513405471. The next prime is 65513405519. The reversal of 65513405473 is 37450431556.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 41092154944 + 24421250529 = 202712^2 + 156273^2 .

It is a cyclic number.

It is not a de Polignac number, because 65513405473 - 2¹ = 65513405471 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (65513405471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42163 + ... + 364423.

It is an arithmetic number, because the mean of its divisors is an integer number (16378482757).

Almost surely, 2^65513405473 is an apocalyptic number.

It is an amenable number.

65513405473 is a deficient number, since it is larger than the sum of its proper divisors (525555).

65513405473 is a wasteful number, since it uses less digits than its factorization.

65513405473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 525554.

The product of its (nonzero) digits is 756000, while the sum is 43.

The spelling of 65513405473 in words is "sixty-five billion, five hundred thirteen million, four hundred five thousand, four hundred seventy-three".