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6551531314231 = 11121158910821
BaseRepresentation
bin101111101010110010110…
…1100100101110000110111
3212012022122111000020222111
41133111211230211300313
51324320014004023411
621533422033111451
71244222024222341
oct137254554456067
925168574006874
106551531314231
1120a65416a0a52
128998926b8587
13386a64584a87
1418914ac78291
15b5648ae3721
hex5f565b25c37

6551531314231 has 4 divisors (see below), whose sum is σ = 6551590336264. Its totient is φ = 6551472292200.

The previous prime is 6551531314217. The next prime is 6551531314319. The reversal of 6551531314231 is 1324131351556.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 6551531314231 - 27 = 6551531314103 is a prime.

It is a super-2 number, since 2×65515313142312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6551531314831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29344200 + ... + 29566621.

It is an arithmetic number, because the mean of its divisors is an integer number (1637897584066).

Almost surely, 26551531314231 is an apocalyptic number.

6551531314231 is a deficient number, since it is larger than the sum of its proper divisors (59022033).

6551531314231 is a wasteful number, since it uses less digits than its factorization.

6551531314231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59022032.

The product of its digits is 162000, while the sum is 40.

Adding to 6551531314231 its reverse (1324131351556), we get a palindrome (7875662665787).

The spelling of 6551531314231 in words is "six trillion, five hundred fifty-one billion, five hundred thirty-one million, three hundred fourteen thousand, two hundred thirty-one".

Divisors: 1 111211 58910821 6551531314231