Base | Representation |
---|---|
bin | 111101000001010010… |
… | …111101110000101111 |
3 | 20021010012102212021102 |
4 | 331001102331300233 |
5 | 2033141110000142 |
6 | 50033252553315 |
7 | 4506434545205 |
oct | 750122756057 |
9 | 207105385242 |
10 | 65520000047 |
11 | 25872371877 |
12 | 1084662283b |
13 | 62422542c8 |
14 | 3257a35075 |
15 | 1a87173532 |
hex | f414bdc2f |
65520000047 has 2 divisors, whose sum is σ = 65520000048. Its totient is φ = 65520000046.
The previous prime is 65519999917. The next prime is 65520000109. The reversal of 65520000047 is 74000002556.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 65520000047 - 210 = 65519999023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 65519999974 and 65520000019.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (65520002047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32760000023 + 32760000024.
It is an arithmetic number, because the mean of its divisors is an integer number (32760000024).
Almost surely, 265520000047 is an apocalyptic number.
65520000047 is a deficient number, since it is larger than the sum of its proper divisors (1).
65520000047 is an equidigital number, since it uses as much as digits as its factorization.
65520000047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 29.
The spelling of 65520000047 in words is "sixty-five billion, five hundred twenty million, forty-seven", and thus it is an aban number.
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